Login | Register   
LinkedIn
Google+
Twitter
RSS Feed
Download our iPhone app
TODAY'S HEADLINES  |   ARTICLE ARCHIVE  |   FORUMS  |   TIP BANK
Browse DevX
Sign up for e-mail newsletters from DevX


Tip of the Day
Language: C++
Expertise: All
Nov 12, 1999

Default Arguments are not Part of a Function's Type

Although the default arguments of a function must appear in its declaration, they are not considered part of its type. Thus, you cannot overload a function by using different default arguments:
         
  void f(int n = 6);
  void f(int n = 0); //error, redefinition of f() above
The attempt to overload f() is illegal because the compiler cannot distinguish between the two versions of f().
Danny Kalev
 
Comment and Contribute

 

 

 

 

 


(Maximum characters: 1200). You have 1200 characters left.

 

 

Sitemap
Thanks for your registration, follow us on our social networks to keep up-to-date