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Tip of the Day
Language: Visual Basic
Expertise: Beginner
Oct 8, 2001

Another Form of Mid() Function


Sometimes, while performing String operations, you may want to extract part of the string from the main string--from the StartPosition to the EndPosition specified. The problem with the Mid() is that it expects only the StartPosition and the number of characters needed from the StartPosition. If you want to extract characters from position 12 to 15 or from m to n where m
 
Private Function MidX(strSource As String, 
StartIndex As Integer, EndIndex
As Integer)
Dim iLength As Integer
    If EndIndex > 0 And EndIndex > StartIndex Then
        iLength = EndIndex - StartIndex + 1
        MidX = Mid(strSource, StartIndex, iLength)
    Else
        Err.Raise 13, "Mid X", "Type Mismatch"
    End If
End Function

Usage: MidX("1234567890",5,7)
Output: 567
Prasad Haridass
 
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