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Tip of the Day
Language: Relational Databases
Expertise: Beginner
Mar 28, 1997



Building the Right Environment to Support AI, Machine Learning and Deep Learning

Pulling Digits Out of String to Sum Them

How do I pull out every second digit from a string and sum them?

This is a rather unusual question, but it's not that hard to accomplish.

What must iterate through each character of the string and "grab" the digits whose position is a multiple of two (2). There are a couple of ways to do this, but I took what I felt was the easier route. Since this is more or less a binary problem, setting a Boolean value with each iteration works nicely. Here's the logic:

  1. For all "odd" positions, set Boolean value to False;
  2. For all "even" positions, set Boolean value to True;
  3. If the Boolean value is true, grab that character and add it to a temporary buffer.
  4. Iterate through the buffer, and convert each character to an Integer while adding the converted value to an integer variable.

Here's the code that accomplishes the above:

function AddEvenOrOddChars(S : String; OddOrEven : Boolean) : Integer;
  I   : Integer;
  evn : Boolean;
  buf : String;
  Result := 0;

  {If OddOrEven was passed as True, then the all odd positions
   will be grabbed and summed. If False, then all even positions
   will be grabbed and summed.}
  evn := EvenOdd;

  {First grab the even position characters}
  for I := 1 to Length(S) do begin
    if evn then
      buf := buf + S[I];

    {Set boolean to its opposite regardless of its current value.
     If it's currently true, then we've just grabbed a character.
     Setting it to False will make the program skip the next one.}
    evn := NOT evn;

  {Now, iterate through the buffer variable to add up the individual
  for I := 1 to Length(buf) do
    Result := Result + StrToInt(buf[I]);
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