Login | Register   
Twitter
RSS Feed
Download our iPhone app
TODAY'S HEADLINES  |   ARTICLE ARCHIVE  |   FORUMS  |   TIP BANK
Browse DevX
Sign up for e-mail newsletters from DevX


Tip of the Day
Language: C++
Expertise: Intermediate
Apr 20, 2007

Avoid Memory Corruption when Assigning a CComBSTR to a CComVariant's bstrVal Member

Although the CComBSTR = operator is overloaded to make a copy of the string, this is not the case when assigning a CComVariant's bstrVal member to a CComBSTR. In this case, you need to make an explicit copy:

CComVariant bstrTarget;
CComBSTR strSource("test");

// Use CComBSTR::Copy to make a copy
// of the source string.
bstrTarget.bstrVal = strSource.Copy();
If you don't make a copy of the source string, it will wind up being freed twice—once by the CComVariant's destructor, and once by the original CComBSTR's destructor.

Alison Lomaka
 
Comment and Contribute

 

 

 

 

 


(Maximum characters: 1200). You have 1200 characters left.

 

 

Sitemap