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Tip of the Day
Language: VB4,VB5,VB6,VBS
Expertise: Intermediate
Jun 26, 1999

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ShiftRight - Shift a Long to the right

' Shift to the right of the specified number of times
'
' NOTE: requires Power2()

Function ShiftRight(ByVal value As Long, ByVal times As Long) As Long
    ' we need to create a mask of 1's corresponding to the
    ' digits in VALUE that will be retained in the result
    Dim mask As Long, signBit As Long
    
    ' return zero if too many times
    If times >= 32 Then Exit Function
    ' return the value if zero times
    If times = 0 Then ShiftRight = value: Exit Function
    
    ' evaluate the sign bit in advance
    signBit = (value < 0) And Power2(31 - times)
    ' create a mask with 1's for the digits that will be preserved
    If times < 31 Then
        ' if times=31 then the mask is zero
        mask = Not (Power2(times) - 1)
    End If
    ' clear all the digits that will be discarded, and
    ' also clear the sign bit
    value = (value And &H7FFFFFFF) And mask
    ' do the shift, without any problem, and add the sign bit
    ShiftRight = (value \ Power2(times)) Or signBit
End Function
Francesco Balena
 
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