Tackling the Conundrums of Constant Expressions

Tackling the Conundrums of Constant Expressions

onstant expressions are tricky. Not all of them have an overt const qualifier. Furthermore, in some cases, a const-qualified variable is just a constant, but not a constant expression. These nuances aren’t just bits of C++ trivia. Rather, they affect the correctness of your code and its performance. The following sections explain the rules of constant integral expressions and show how to avert common mishaps.

How do you know whether an expression is a constant expression? How do you turn a non-constant expression into a constant expression when necessary?

Learn the rules of constant integral expressions.

In the following cases, C++ requires expressions that evaluate to an integral constant expression:

Contrary to popular conception, not every const variable of an integral type is a constant expression. Consider the following two examples:

struct C{ inline static int getval() {return 4;}};const int MAX=1024;const int MIN=C::getval();

Both MAX and MIN are constants, eg., the program can’t modify their values. However, there is a substantial difference between them. MAX is a constant integral expression. As such, it can be used in an array declaration, case labels, etc.:

char buff[MAX];int sizes=getsizes();switch (sizes){case MAX://.. break;default://.. break;};

What about MIN? Syntactically speaking, it’s a const object with an initializer, just as MAX is. However, if you try to use MIN in places where an integral constant expression is required, your compiler will complain:

struct bitpattern{ signed nibble: MIN;//error: constant expression required unsigned octet: 8; };enum SIZES { S=MIN, //error: constant expression required L=512,  XL=MAX //fine};

In the examples above, a compilation error reveals that MIN isn’t a constant expression. In fact, this is your litmus test: use a constant as an enumerator’s initializer to check whether it’s a valid constant expression.

Compile-time Evaluation
In time critical applications, constants are often chosen for performance reasons i.e., to ensure compile time evaluation of expressions. MIN can be evaluated at compile-time if C::getval() is inlined (every decent compiler will inline the call anyway). Thus, performance-wise, MIN and MAX are equally efficient. However, MIN isn’t an integral constant expression even when C::getval() is inlined since the rules of constant integral expressions are very strict. To qualify as a constant expression, MIN‘s initializer must be one of the following:

  • A literal such as 5, 8ul, ‘z’, and false
  • An enumerator
  • A sizeof expression
  • A const static data member initialized with a constant expression

To turn MIN into a constant expression, it’s therefore necessary to replace the C::getval() call with a literal. If you’re concerned about the maintenance problems that hard-coded literals might incur, use a macro instead. Yes, in spite of the fair criticism that macros often attract, they are still useful in some cases, so to speak:

#ifndef C_GETVAL#define C_GETVAL 4#endifconst int MIN=C_GETVAL;

Lo and behold, MIN is now a valid constant expression:

enum SIZES { S=MIN, //now OK L=512,  XL=MAX //fine};

Const Static Data Members
const static data members initialized by a constant expression require special attention. Seemingly, the recursive definition ensures that every const static member whose initializer is a constant expression is also a valid constant expression. This isn’t always true, though. Consider the following counter example:

struct C{ const static int X;};const int Y=C::X;const int C::X=2; //initialized by a constant expression

The static member X is initialized with a literal. The constant Y looks as a constant expression because its initializer C::X is seemingly a constant expression. Well, not quite:

char arr[Y];//error, constant expression required

Actually, neither C::X nor Y is a constant expression! The order of their definitions makes all the difference. The definition of Y uses C::X as the initializer but at this point, C::X hasn’t been defined yet. Consequently, the static initialization of Y is silently replaced with dynamic initialization, which means that Y is no longer a constant expression. Replacing the order of the definitions fixes this mess:

 const int C::X=2;  const int Y=C::X;//Y is now a constant expressionchar arr1[Y], arr2[C::X] //OK

Of course, you can eliminate such mishaps by using in-class initialization:

struct C{ const static int X=2;};

This will guarantee that C::X is a constant expression.

A Programmer’s Best Friend
The standards committee is now working on a mechanism that will allow programmers to use inline functions as initializers of constant expressions (further information on this proposal is available here). However, for the time being, you can use a macro?unsavory as this may seem.

With respect to const static data members of an integral type, the best policy is to use in-class initializers. However, older compilers don’t support in-class initializations. If you’re using such a compiler, always initialize const static members before using them or better yet, replace them with nameless enums.

To check whether your constants qualify as constant expressions, use them as initializers of dummy enumerators. This way your loyal compiler becomes the “constant expression watchdog”, alerting you whenever an expression that should be a constant expression isn’t really so.

Share the Post:
XDR solutions

The Benefits of Using XDR Solutions

Cybercriminals constantly adapt their strategies, developing newer, more powerful, and intelligent ways to attack your network. Since security professionals must innovate as well, more conventional endpoint detection solutions have evolved

AI is revolutionizing fraud detection

How AI is Revolutionizing Fraud Detection

Artificial intelligence – commonly known as AI – means a form of technology with multiple uses. As a result, it has become extremely valuable to a number of businesses across

AI innovation

Companies Leading AI Innovation in 2023

Artificial intelligence (AI) has been transforming industries and revolutionizing business operations. AI’s potential to enhance efficiency and productivity has become crucial to many businesses. As we move into 2023, several

data fivetran pricing

Fivetran Pricing Explained

One of the biggest trends of the 21st century is the massive surge in analytics. Analytics is the process of utilizing data to drive future decision-making. With so much of

kubernetes logging

Kubernetes Logging: What You Need to Know

Kubernetes from Google is one of the most popular open-source and free container management solutions made to make managing and deploying applications easier. It has a solid architecture that makes

ransomware cyber attack

Why Is Ransomware Such a Major Threat?

One of the most significant cyber threats faced by modern organizations is a ransomware attack. Ransomware attacks have grown in both sophistication and frequency over the past few years, forcing

data dictionary

Tools You Need to Make a Data Dictionary

Data dictionaries are crucial for organizations of all sizes that deal with large amounts of data. they are centralized repositories of all the data in organizations, including metadata such as