If you do a lot of floating-point division operations in VB, you can optimize these operations by multiplying by the reciprocal value. For example, instead of performing this calculation:
X/YDo this:
X * (1 / Y)You can see how this works in VB by adding this code to a form in a new project:
Private Declare Function GetTickCount Lib _ "kernel32" () As LongConst NORMAL As Double = 1453Const RECIPROCAL As Double = 1 / NORMALConst TOTAL_COUNT As Long = 10000000Private Sub Form_Click() Dim dblRes As Double Dim lngC As Long Dim lngStart As Long On Error GoTo Error_Normal lngStart = GetTickCount For lngC = 1 To TOTAL_COUNT dblRes = Rnd / NORMAL Next lngC MsgBox "Normal Time: " & GetTickCount - lngStart lngStart = GetTickCount For lngC = 1 To TOTAL_COUNT dblRes = Rnd * RECIPROCAL Next lngC MsgBox "Reciprocal Time: " & GetTickCount - lngStartExit SubError_Normal: MsgBox Err.Number & " - " & Err.DescriptionEnd SubI
