InstrWordEx – Find a whole word, with your choice of delimiters

InstrWordEx – Find a whole word, with your choice of delimiters

'------------------------------------------------------------------------' This enum is used by both InstrWordEx and ReplaceWordEx'' It uses a binary value to determine what separator characters are allowed' bit 0 = allow spaces' bit 1 = allow symbols' bit 2 = allow control chars' bit 3 = allow digits' If all are excluded (ie a value of 0) then this means char must match a ' special separator provided by callerEnum sepType    specialSep = 0                  'binary 0000 = words are ONLY separated by                                     ' a specified separator    spacesOnly = 1                  'binary 0001 = words must be separated By                                     ' spaces    spacesAndSymbols = 3            'binary 0011 = words must be separated By                                     ' spaces Or symbols    spacesSymbolsAndCtrl = 7        'binary 0111 = words are separated by                                     ' spaces, symbols or ctrl chars    spacesSymbolsCtrlAndDigits = 15 'binary 1111 = words are separated by                                     ' anything but lettersEnd Enum' Return the next occurrence of a whole word'' Based on InstrWord function from VB2TheMax -'' Changes from VB2TheMax function were made by Peter Stubbs to allow ' specification of' what constitutes a separator between words''---------------------------------------------------------------------------'Contact Peter at [email protected]''---------------------------------------------------------------------------'' Choices for separator are as described above for the sepType enum'' Examples:' pos = InstrWordEx(1,"This is a string","is",vbTextCompare)'   returns 6 in pos since there is a word "is" preceded and followed by a Space'' pos = InstrWordEx(1,"This-is-a-string","is",vbTextCompare)'  returns 6 in pos since there is a word "is" preceded and followed by a symbol'' pos = InstrWordEx(1,"This-is-a-string","is",vbTextCompare,spacesOnly)'   returns 0 in pos since there are no occurences of "is" preceded and ' followed by a space'' pos = InstrWordEx(1,"This is a list of 310 things","31",vbTextCompare)'  returns 19 in pos since the digits 31 are preceded by a space and followed ' by a digit'  which is, by default, considered a valid separator'' pos = InstrWordEx(1,"This is a list of 310 ' things","31",vbTextCompare,spacesAndSymbols)'  returns 0 in pos since this specifies spaces and symbols (but not digits) ' are valid separators'' pos = InstrWordEx(1,"This/is/a/string","is",vbTextCompare,specialSep,"/")'   returns 6 in pos since the word "is" is both preceded and followed by /'Function InstrWordEx(Start As Long, Source As String, Find As String, _    compareMethod As VbCompareMethod, Optional separatorType As sepType = _    spacesSymbolsCtrlAndDigits, Optional Separator As String = vbNullString) As _    Long    Dim index As Long    Dim charcode As Integer    Dim separatorInvalid As Boolean    ' assume the search fails    InstrWordEx = 0    index = Start - 1    Do        ' search the next occurrence, exit if not found        index = InStr(index + 1, Source, Find, compareMethod)        If index = 0 Then Exit Function        If index > 1 Then            charcode = Asc(UCase$(Mid$(Source, index - 1, 1)))        Else            charcode = 32        End If        ' check that it is preceded by a valid separator        If IsValidChar(charcode, separatorType, Separator) Then            ' check that it is followed by a valid separator            charcode = Asc(UCase$(Mid$(Source, index + Len(Find), 1)) & " ")            If IsValidChar(charcode, separatorType, Separator) Then                InstrWordEx = index                Exit Function            End If        End If    LoopEnd Function'This function determines if the character value in char is an acceptable ' separator of the'type specified by separatorType'The function is used by both InstrWordEx and ReplaceWordExPrivate Function IsValidChar(char As Integer, separatorType As sepType, _    Separator As String)    Dim charType As Integer    'Ctrl are chars in charType 0-31    'Spaces and symbols are chars in charType 32-47, 58-64 and 91-255    'Digits are chars in charType 48-57    If separatorType = specialSep Then        IsValidChar = (char = Asc(UCase$(Separator)))        Exit Function    End If    'Determine charType that char falls in    Select Case char         Case Is < 32 '0-32 = ctrl            charType = 4 '0100 binary         Case 32 'space            charType = 1 '0001 binary         Case Is < 48, Is > 90 '32-48 or 91-255 = symbols (first range)            charType = 2 '0010 binary         Case Is < 58 '48-57 = digits            charType = 8 '1000 binary         Case Is < 65 '58-64 = symbols (second range)            charType = 2 '0010 binary        Case Else 'it's a letter            charType = 0 '0000 binary    End Select    IsValidChar = Not ((charType And separatorType) = 0)End Function

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