Question:
Hi,got a problem with a cast. Maybe someone out there knows how to solve it. How can I get this void pointer to act like (point to) my object?example:
myClass* mc; void *vp; mc = new myClass; vp = (void *)mc; vp->some_func(); //this doesn’t work! Why! //Bjorn
Answer:
Because vp is a void pointer, it has no way to determine the address of some_func relative to the value of vp.You can work around this two ways. One is to use a pointer of the appropriate type. The other is to type cast the void pointer when you use it like this:
myClass* mc; void *vp; mc = new myClass; vp = (void *)mc; ((myClass*)vp)->some_func();