devxlogo

Read the Contents of a Zip File Using the java.util.zip Package

Read the Contents of a Zip File Using the java.util.zip Package

This example code extracts the content of a zip file (the name of the zip file is supplied in args[0]). First, open the zip file using ZipFile class, then loop through all entries in the zip file and extract the content. If one entry is a directory then create it.

 import java.util.zip.*;import java.util.*;import java.io.*;public class ReadZipFile{	public static void main(String args[]) throws Exception{//first argumentis zip file name		if(args.length==0){			System.out.println("Zip file name is missing");			return;		}		ZipEntry ze;		byte buf[];		FileOutputStream fout;		File dir;		ZipFile zf=new ZipFile(args[0]);		Enumeration zentries=zf.entries();		while(zentries.hasMoreElements()){			ze=(ZipEntry)zentries.nextElement();			System.out.println(ze.getName());			if(!ze.isDirectory()){				buf=new byte[(int)ze.getSize()];	//create buffer to store data				zf.getInputStream(ze).read(buf);	//read data from file in zip file				fout=new FileOutputStream(ze.getName());				fout.write(buf);	//write data to file				fout.close();			}else{				dir=new File(ze.getName());	//create directory				dir.mkdir();			}		}		zf.close();	}}
See also  Redefining Energy Management: Advanced Solutions for Modern Buildings
devxblackblue

About Our Editorial Process

At DevX, we’re dedicated to tech entrepreneurship. Our team closely follows industry shifts, new products, AI breakthroughs, technology trends, and funding announcements. Articles undergo thorough editing to ensure accuracy and clarity, reflecting DevX’s style and supporting entrepreneurs in the tech sphere.

See our full editorial policy.

About Our Journalist