Using the count_if() Algorithm

Using the count_if() Algorithm

You can use the count_if() algorithm to count the number of elements in a container based on any condition. count_if() takes three arguments. The first and second argument areinput iterators defining the range of search within the container and the third one takes a function pointer or a function object implenting the condition based on which you want to count elements.

For instance, suppose you have a vector of strings and you want to find the total count of non-alphanumeric strings. First, you define a function object to be used as the third argument of count_if():

class FindNonAlphaNum{public:	bool operator () (const string& str)	{		for (int i = 0; i < str.size(); ++i)		{			if (!isalnum(str[i]))				return true;		}		return false;	}};int main (){	vector vecstr;	vecstr.push_back("aaaaaa#aa");	vecstr.push_back("zz2zz");	vecstr.push_back("yy3yy");	int count = count_if(vecstr.begin(), vecstr.end(), FindNonAlphaNum());	cout << "The total number of non-alphanumeric strings is "endl << count << endl;// output will be 1}
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