Generation of Equivalent Binary Code of Decimal Digits

Generation of Equivalent Binary Code of Decimal Digits

This is C source code, written in gcc platform (Ubuntu, 14.04 LTS, Linux).

Here is the process for generating the Equivalent Binary Code of a decimal digit. First, a palindrome number is being generated. If we Push n elements in the stack, it generates a palindrome number of length (2^n) -1.

This is the special property. Then it can generate Binary code of maximum n bit. Note that, we have to Push elements sequentially in Decreasing order. e.g 4,3,2,1. It generates 121312141213121, so now it can generate Binary code of maximum 4 bit.

/*   This is a Process of generating Palindrome number from some given numbers.      This is a Process of generating binary code from some given numbers.      It actually takes the help of palindrome generation.*/#include #define max 10#define maxim 300#define maxr 550#define maxc 9int pushA (int[], int*, int*);int cpyAC (int[], int[], int*);int palgen (int[], int[], int[], int*, int*);void display (int[], int*);void displayA (int[], int*);int binarycode (int A[maxr][maxc], int*, int*, int[], int*);void grycddisp (int A[maxr][maxc], int*, int*);//----------------------------------------------------int pushA (int a[max], int *top, int *item){    printf("
	Enter element: ");    scanf("%d", &(*item));    a[++(*top)] = (*item);    printf("
	Push is successful...
");    return (*top);}//----------------------------------------------------int cpyAC (int a[max], int c[max], int *top){  int i= -1, j= -1, toc;  while (j      c[++i] = a[++j];  toc= i;        return (toc);}//----------------------------------------------------int palgen (int a[max], int b[maxim], int c[max], int *top, int *toc){  int i, j, k, tob, x;  j= -1;  i= (*top);           k= (*toc);           while (k  -1)  {    b[++j] = c[k];    (*toc)--;    k= (*toc);    while (b[j] != a[i])    {      i--;    }    while (i      {      c[++k] = a[++i];      (*toc)++;          i+= 0;    }    (*toc)--;    k = (*toc);    k+= 0;     }  tob= j;           return (tob);  }//---------------------------------------------------int binarycode (int A[maxr][maxc], int *row, int *col, int b[maxim], int *tob){printf("

		Row= %d, Col= %d

", *row, *col);               //create co-ordinate  int i=0, j, value, k;  while (i    {    j=(*col);    while (j 0 )    {      j--;    }    i++;  }               //binarycode generation  i= 0;  j= (*col);  while (j  0)  {    A[i][j] = 0;      j--;  }  while (i   {    i++;     j=(*col);    while (j0)    {      A[i][j] = A[i-1][j];      j--;    }    k= (*tob);    value = b[k];    (*tob)--;    j= value;    for(; j0; j--)    {          if (A[i][j] == 0)        A[i][j] = 1;      else        A[i][j] = 0;    }    i+=0;  }}//------------------------------------------------------------void grycddisp (int A[maxr][maxc], int *row, int *col){  int i= 0, j;  while (i    {    j=(*col);    while (j 0 )    {      printf("		%d", A[i][j]);      j--;    }    printf("
");    i++;  }}//------------------------------------------------------------void displayA (int a[max], int *top){  int i;  printf("
	You entered...
");  i= (*top);  while (i = 0)  {    printf("
	%d", a[i--]);  }}//---------------------------------------------------void display (int b[maxim], int *tob){  int i;  printf("
	The items of Stack are shown...{B}
");  i= (*tob);  printf("

		");  while (i = 0)  {    printf("%d", b[i--]);  }}//----------------------------------------------------void main (void){  int a[max], b[maxim], c[max], item=0, top =(-1), toc, tob;  int A[maxr][maxc], row =1, col =0, bit =0;  char ch;  system ("clear");  printf ("
	This is a Process of generating binary Code of n-bit.
	Please insert n numbers in decreasing order.
	e.g 4,3,2,1 for 4-bit binary code.

");  if (top == -1)    printf("
	Initially Stack is empty...
");    printf("
	You have to give data, please start insertion.
	Press 'y' for insert, 'n' for exit.

");  ch= getchar();  while (ch == 'y')   {    top= pushA (a, &top, &item);    printf("
	'y' :insert
	'n' :exit.
");    getchar();        ch= getchar();    getchar();    if( top == (max-1) )    {      printf("
	Stack is full.
	Push operation is not possible...

");      break;    }  }  system("clear");  displayA (a, &top);  if(top == -1)    printf("
	Stack is empty...
	Copy is done...

");  else   toc= cpyAC (a, c, &top);           tob= palgen (a, b, c, &top, &toc);        if(tob == -1)    printf("
	Stack is empty...

");  else    display (b, &tob);//-------------------------------------------------------  printf("
	Enter the bit number of binary code: ");  scanf("%d", &bit);  col= bit;  while (bit  0)  {    row= (row*2);    bit --;  }    binarycode (A, &row, &col, b, &tob);  grycddisp (A, &row, &col);  printf ("

	T  H  A  N  K    Y  O  U

");  }
Share the Post:
Heading photo, Metadata.

What is Metadata?

What is metadata? Well, It’s an odd concept to wrap your head around. Metadata is essentially the secondary layer of data that tracks details about the “regular” data. The regular

XDR solutions

The Benefits of Using XDR Solutions

Cybercriminals constantly adapt their strategies, developing newer, more powerful, and intelligent ways to attack your network. Since security professionals must innovate as well, more conventional endpoint detection solutions have evolved

AI is revolutionizing fraud detection

How AI is Revolutionizing Fraud Detection

Artificial intelligence – commonly known as AI – means a form of technology with multiple uses. As a result, it has become extremely valuable to a number of businesses across

AI innovation

Companies Leading AI Innovation in 2023

Artificial intelligence (AI) has been transforming industries and revolutionizing business operations. AI’s potential to enhance efficiency and productivity has become crucial to many businesses. As we move into 2023, several