Say you’ve got a function that takes some built-in kind of parameter. You need to make that function work?even for an object (which has a data member of that built-in type type)?all without changing the syntax of your function call statement. This code can do it for you:
class INT{public: INT( int t): y(t) {} operator int () { return y; }private: int y;};void func (int y){ cout << y;}int main (){ int t = 9; func(t); INT obj_INT(6); func(obj_INT);}
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