dcsimg
TODAY'S HEADLINES  |   ARTICLE ARCHIVE  |   FORUMS  |   TIP BANK
Browse DevX
Sign up for e-mail newsletters from DevX


Tip of the Day
Language: Java
Expertise: Intermediate
Feb 14, 2002

WEBINAR:

On-Demand

Building the Right Environment to Support AI, Machine Learning and Deep Learning


Run Java Applications Using the Many JARs File


You can do this without using the classpath directive at the command line. How? Easy! Just write a launcher! Here's the code:
 
/*
	Allow you to type "java QuickRunner"
	instead of "java -classpath foo.jar;bar.jar;. MyApp
*/

public class QuickRunner
{
    public static void main(String args[])
    {
        try
        {
            String defaultClassPath =
System.getProperty("java.class.path");
            String fileSep = System.getProperty("file.separator");
            String pathSep = System.getProperty("path.separator");
            String currDir = ".";
            String beanJars = "foo.jar" + pathSep + "bar.jar; // _
the jar
file needed by the application
            String myClassPath = currDir + pathSep + beanJars + _
pathSep +
defaultClassPath;
            String env[] = new String[1];
            env[0] = "CLASSPATH=" + myClassPath;
            String command = "java MyApp";
            Process p = Runtime.getRuntime().exec(command, env);
            new InputStreamMonitor(p.getInputStream());
            new InputStreamMonitor(p.getErrorStream());
            p.waitFor();
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
    }
}
Tanguy De
 
Comment and Contribute

 

 

 

 

 


(Maximum characters: 1200). You have 1200 characters left.

 

 

Sitemap
Thanks for your registration, follow us on our social networks to keep up-to-date