dcsimg
Login | Register   
RSS Feed
Download our iPhone app
TODAY'S HEADLINES  |   ARTICLE ARCHIVE  |   FORUMS  |   TIP BANK
Browse DevX
Sign up for e-mail newsletters from DevX

By submitting your information, you agree that devx.com may send you DevX offers via email, phone and text message, as well as email offers about other products and services that DevX believes may be of interest to you. DevX will process your information in accordance with the Quinstreet Privacy Policy.


Tip of the Day
Language: VB4,VB5,VB6
Expertise: Intermediate
Apr 26, 1999

WEBINAR:

On-Demand

Application Security Testing: An Integral Part of DevOps


Process string characters using Byte arrays

When you need to process each character in a string, you can assign the string to a byte array and iterate on its elements (remember: each Unicode character corresponds to two bytes). This approach is usually much faster because it saves a lot of Mid$ functions and, hence, a lot of temporary strings. Here is a very fast way to count the spaces in a string:

Dim b() as Byte, count As Integer
b() = source$
For i = 0 to UBound(b) Step LenB("A")
    If b(i) = 32 Then count = count + 1
Next
Note the unorthodox usage of the LenB() function: it returns 2 under VB4/32, VB5 and VB6, and 1 under VB4/16, so that you can use the same code fragment without the need for a #If compiler directive.

Beware: this technique might not work if you then localize your code for foreign countries that make use of the full Unicode character set.

Francesco Balena
 
Comment and Contribute

 

 

 

 

 


(Maximum characters: 1200). You have 1200 characters left.

 

 

Sitemap
Thanks for your registration, follow us on our social networks to keep up-to-date