Brackets are well balanced if each ‘(‘ has its ‘)’. The argument str represents the array of characters which contains the expression.

The following function returns 0 if the brackets in the expression are well balanced, and a nonzero integer if not.

int balanced(char *str){   int balance=0;  // Balance indicator.   char c;  // Current character.   int i=0;  // Character index.   // Read characters.   while((c=str[i++]) != '')   {      // When '(' is read, increase indicator.      if(c=='(') balance++;      // When ')' is read, decrease indicator.      if(c==')') balance--;   }   return balance;}