' A variant of the Split function, that offers the following improvements' You can pass text qualifier as the third argument and optionally specify' to treat consecutive occurrences of delimiters as one' For example, the following source text contains comma inside one of the ' fields, so the' regular Split function will parse it incorrectly:' "Bayazitov","Ernest","2500 Data Drive, 100A, Sacramento, CA 95630",,,,10,,2,' ,,' Also, it has some empty fields, which do not have any values or text ' qualifiers.' In this case, we need to specify comma as delimiter and double quote ' character As Text' qualifier, and do not treat consecutive occurrences of delimiters as one'' Usage:' Dim res() As String' res() = SplitWithQualifiers("""Bayazitov"",""Ernest"",""2500 Data Drive, ' 100A, Sacramento, CA 95630"",,,,10,,2,,,", ",", """", False)Public Function SplitWithQualifiers(ByVal SourceText As String, _ ByVal TextDelimiter As String, ByVal TextQualifier As String, _ Optional ByVal TreatMultipleDelimitersAsOne As Boolean) As String() Dim strTemp() As String, strRes() As String, I As Long, J As Long, _ A As strng, B As String, blnStart As Boolean If TreatMultipleDelimitersAsOne Then Do While (InStr(1, SourceText, TextDelimiter & TextDelimiter) And (I < _ 100)) SourceText = Replace(SourceText, TextDelimiter & TextDelimiter, _ TextDelimiter) I = I + 1 Loop End If If TextDelimiter <> " " Then SourceText = Trim$(SourceText) strTemp() = Split(SourceText, TextDelimiter) For I = 0 To UBound(strTemp) J = InStr(1, strTemp(I), TextQualifier, vbTextCompare) If J Then A = Replace(strTemp(I), TextQualifier, "") Select Case strTemp(I) Case TextQualifier & A & TextQualifier ' "xxx" B = B & A & vbCrLf blnStart = False Case TextQualifier & A ' "xxx B = B & A & TextDelimiter blnStart = True Case A ' xxx B = B & A & TextDelimiter blnStart = False Case A & TextQualifier ' xxx" B = B & A & vbCrLf blnStart = False End Select Else If blnStart Then B = B & strTemp(I) & TextDelimiter Else B = B & strTemp(I) & vbCrLf End If End If Next I If B <> "" Then B = Left$(B, Len(B) - 2) strRes() = Split(B, vbCrLf) Else ReDim strRes(0) strRes(0) = SourceText End If SplitWithQualifiers = strRes()End Function


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