devxlogo

Extract the Contents of ZIP/JAR Files Programmatically

Extract the Contents of ZIP/JAR Files Programmatically

Suppose jarFile is the jar/zip file to be extracted. destDir is the path where it will be extracted:

java.util.jar.JarFile jar = new java.util.jar.JarFile(jarFile);java.util.Enumeration enum = jar.entries();while (enum.hasMoreElements()) {	java.util.jar.JarEntry file = (java.util.jar.JarEntry) enum.nextElement();	java.io.File f = new java.io.File(destDir + java.io.File.separator + file.getName());	if (file.isDirectory()) { // if its a directory, create it		f.mkdir();		continue;	}	java.io.InputStream is = jar.getInputStream(file); // get the input stream	java.io.FileOutputStream fos = new java.io.FileOutputStream(f);	while (is.available() > 0) {  // write contents of 'is' to 'fos'		fos.write(is.read());	}	fos.close();	is.close();}
See also  5 Tips for Working With an Onsite Interpreter
devxblackblue

About Our Editorial Process

At DevX, we’re dedicated to tech entrepreneurship. Our team closely follows industry shifts, new products, AI breakthroughs, technology trends, and funding announcements. Articles undergo thorough editing to ensure accuracy and clarity, reflecting DevX’s style and supporting entrepreneurs in the tech sphere.

See our full editorial policy.

About Our Journalist