Returning the Last Day of a Month

Returning the Last Day of a Month

Question:
I have a form from which I am searching a database.The search is being conducted between a startdate and an enddate.As the default I’d like to have the first and last day of the last month.

Year(Now()) & Month(Now())-1 & “01” returns the first day of month -1, but how do I do to get the last day?

Answer:
Try this using VB6:

Dim d As DateDim n As IntegerDim dEndofMonthd = Month(Now) + 1 & "/1/" & Year(Now)n = DateDiff("d", Now, d)dEndofMonth = Now + (n-1)
Share the Post:
data observability

Data Observability Explained

Data is the lifeblood of any successful business, as it is the driving force behind critical decision-making, insight generation, and strategic development. However, due to its intricate nature, ensuring the

Heading photo, Metadata.

What is Metadata?

What is metadata? Well, It’s an odd concept to wrap your head around. Metadata is essentially the secondary layer of data that tracks details about the “regular” data. The regular

XDR solutions

The Benefits of Using XDR Solutions

Cybercriminals constantly adapt their strategies, developing newer, more powerful, and intelligent ways to attack your network. Since security professionals must innovate as well, more conventional endpoint detection solutions have evolved