Question:
I tried using the replace function as shown below, but I receive an error on using “Next i”.

Function formatOutput( theText )Dim iDim sNewStringFor i = 1 to Len(theText)     If Mid(theText, i, 1) <> "’" Then     sNewString = sNewString &  Mid(theText, i, 1)  End IfNext iEnd Function

The error reads: “Expected end of statement”.If I take the i out, I receive a blank output which I’m assuming is because I’ve stopped the loop. What am I doing wrong?
As soon as I can get this working I’d like to try assigning two single quotes as the value of an extra variable to replace all single quotes with two.

Answer:
The Replace function isn’t the issue…Next i is. VBScript does not list the variable following the Next keyword.
Simply remove the i so that the line is just Next, and you’re all set. I typically leave the variable following the Next keyword in a comment, like so:

Next  ’ i

Otherwise, I get confused.