How can you tell which f2() will be invoked: A::f2() method or B::f2()? In the following code, f1 is not virtual?thus, it calls A::f1(); which in turn calls the f2() function. Because f2() is virtual, it doesnt call A::f2() it calls B::f2().
class A{public: void f1(){cout<<"A::f1 invoked "<
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