# Palindrome Generation

This is a code is written with the gcc platform (Ubuntu, LINUX); however, since it is C-based code, it should be portable. The listing generates a palindrome number from some given numbers. The operation is based on stack and will actually generate the palindrome of length ( 2n -1 ) for a given n numbers, so if n is 3, then this would be (23-1), which is 8 – 1, and thus 7. This is the special property.

I hope, this may help the beginners.

The code:

``````/*	This is a Process of generating Palindrome number from some given numbers	*/#include #define max 10#define maxim 30int pushA (int[], int*, int*);int cpyAC (int[], int[], int*);int palgen (int[], int[], int[], int*, int*);void display (int[], int*);//void displayC (int[], int*);void displayA (int[], int*);//----------------------------------------------------int pushA (int a[max], int *top, int *item){    printf("
Enter element: ");    scanf("%d", &(*item));    a[++(*top)] = (*item);    printf("
Push is successful...
");    return (*top);}//----------------------------------------------------int cpyAC (int a[max], int c[max], int *top){   int i= -1, j= -1, toc;   while (j < *top)      c[++i] = a[++j];   toc= i;		   return (toc);}//----------------------------------------------------int palgen (int a[max], int b[maxim], int c[max], int *top, int *toc){   int i, j, k, tob, x;   j= -1;   i= (*top);			   k= (*toc);			   while (k > -1)   {      b[++j] = c[k];      (*toc)--;      k= (*toc);      while (b[j] != a[i])      {          i--;      }      while (i <= (*top))      {          c[++k] = a[++i];         (*toc)++;              i+= 0;      }      (*toc)--;      k = (*toc);      k+= 0;   }   tob= j;			   return (tob);}//----------------------------------------------------/*void displayC (int c[max], int *toc){   int i;   printf("
The items of Stack are shown...{C}
");   i= (*toc);   while (i >= 0)   {      printf("
%d:	%d", i, c[i--]);   }}*///---------------------------------------------------void displayA (int a[max], int *top){   int i;   printf("
You entered...
");   i= (*top);   while (i >= 0)   {      printf("
%d", a[i--]);   }}//---------------------------------------------------void display (int b[maxim], int *tob){   int i;   printf("
The items of Stack are shown...{B}
");   i= (*tob);   printf("

");   while (i >= 0)   {      printf("%d", b[i--]);   }}//----------------------------------------------------void main (void){   int a[max], b[maxim], c[max], item=0, top =(-1), toc, tob;   char ch;   system ("clear");   printf ("
This is a Process of generating Palindrome number from some given numbers

");   if (top == -1)      printf("
Initially Stack is empty...
");     printf("
You have to give data, please start insertion.
Press 'y' for insert, 'n' for exit.

");   ch= getchar();   while (ch == 'y')    {      top= pushA (a, &top, &item);      printf("
'y' :insert
'n' :exit.
");      getchar();          ch= getchar();      getchar();      if( top == (max-1) )      {          printf("
Sorry...
Stack is full.
Push operation is not possible...

");         break;      }    }   system("clear");   displayA (a, &top);   if(top == -1)      printf("
Sorry...
Stack is empty...
Copy is done...

");   else     toc= cpyAC (a, c, &top);			   //  displayC (c, &toc);   tob= palgen (a, b, c, &top, &toc);		   if(tob == -1)      printf("
Sorry...
Stack is empty...

");   else      display (b, &tob);   printf ("

T  H  A  N  K    Y  O  U

");  }``````

At DevX, we’re dedicated to tech entrepreneurship. Our team closely follows industry shifts, new products, AI breakthroughs, technology trends, and funding announcements. Articles undergo thorough editing to ensure accuracy and clarity, reflecting DevX’s style and supporting entrepreneurs in the tech sphere.

See our full editorial policy.